CDPL.Base.VoidLookupKeyAnyFunctor Class Reference

A wrapper class for various types of callable objects. More...

Inheritance diagram for CDPL.Base.VoidLookupKeyAnyFunctor:

Public Member Functions
None	__init__ ()
	Contructs the VoidLookupKeyAnyFunctor instance.
None	__init__ (VoidLookupKeyAnyFunctor func)
	Contructs a copy of the VoidLookupKeyAnyFunctor instance func. More...
None	__init__ (object callable)
	Contructs the VoidLookupKeyAnyFunctor instance for the specified callable object. More...
None	__call__ (LookupKey arg1, Any arg2)
	Invokes the wrapped callable object with the given arguments. More...
bool	__bool__ ()
	Tells whether the instance holds a callable object. More...
bool	__nonzero__ ()
	Tells whether the instance holds a callable object. More...

Detailed Description

A wrapper class for various types of callable objects.

Constructor & Destructor Documentation

__init__() [1/2]

None CDPL.Base.VoidLookupKeyAnyFunctor.__init__

(

VoidLookupKeyAnyFunctor

func

)

Contructs a copy of the VoidLookupKeyAnyFunctor instance func.

Parameters

func	The VoidLookupKeyAnyFunctor instance to copy.

__init__() [2/2]

None CDPL.Base.VoidLookupKeyAnyFunctor.__init__

(

object

callable

)

Contructs the VoidLookupKeyAnyFunctor instance for the specified callable object.

Parameters

callable

The callable object to wrap.

Member Function Documentation

__call__()

None CDPL.Base.VoidLookupKeyAnyFunctor.__call__	(	LookupKey	arg1,
		Any	arg2
	)

Invokes the wrapped callable object with the given arguments.

Parameters

arg1	The first argument to forward.
arg2	The second argument to forward.

Returns

The obtained return value.

__bool__()

bool CDPL.Base.VoidLookupKeyAnyFunctor.__bool__

(

)

Tells whether the instance holds a callable object.

Returns

True if the instance holds a callable object, and False otherwise.

__nonzero__()

bool CDPL.Base.VoidLookupKeyAnyFunctor.__nonzero__

(

)

Tells whether the instance holds a callable object.

Returns

True if the instance holds a callable object, and False otherwise.